220 19959 <1c31275e-3bac-4eb2-99cf-256b14e6f650@isocpp.org> article Path: news.gmane.org!not-for-mail From: NDos Dannyu Newsgroups: gmane.comp.lang.c++.isocpp.proposals Subject: Re: Address of a reference: determining the value category of what it refers? Date: Fri, 21 Aug 2015 22:15:57 -0700 (PDT) Lines: 121 Approved: news@gmane.org Message-ID: <1c31275e-3bac-4eb2-99cf-256b14e6f650@isocpp.org> References: <76fe342f-3342-4355-af20-1c41b21e54aa@isocpp.org> <3183929.eXnTES4BH3@tjmaciei-mobl4> <13312961.n5JFXrPRMR@tjmaciei-mobl4> Reply-To: std-proposals@isocpp.org NNTP-Posting-Host: plane.gmane.org Mime-Version: 1.0 Content-Type: multipart/mixed; boundary="----=_Part_537_790931100.1440220558026" X-Trace: ger.gmane.org 1440220561 2379 80.91.229.3 (22 Aug 2015 05:16:01 GMT) X-Complaints-To: usenet@ger.gmane.org NNTP-Posting-Date: Sat, 22 Aug 2015 05:16:01 +0000 (UTC) To: ISO C++ Standard - Future Proposals Original-X-From: std-proposals+bncBCX7FRO67EHRBD4L4CXAKGQESWLB4EA@isocpp.org Sat Aug 22 07:16:01 2015 Return-path: Envelope-to: gclcip-std-proposals@m.gmane.org Original-Received: from mail-io0-f198.google.com ([209.85.223.198]) by plane.gmane.org with esmtp (Exim 4.69) (envelope-from ) id 1ZT19t-0006y6-4V for gclcip-std-proposals@m.gmane.org; Sat, 22 Aug 2015 07:16:01 +0200 Original-Received: by iodt126 with SMTP id t126sf157058739iod.0 for ; Fri, 21 Aug 2015 22:16:00 -0700 (PDT) X-Google-DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=1e100.net; s=20130820; h=x-gm-message-state:date:from:to:message-id:in-reply-to:references :subject:mime-version:content-type:x-original-sender:reply-to :precedence:mailing-list:list-id:x-spam-checked-in-group:list-post :list-help:list-archive:list-subscribe:list-unsubscribe; bh=O+xouClz0EV3089bshqf1ORvq0lUk5QS+Z7wqfsqLCc=; b=bR0v2meilgTDvixnYMziazDTbgPpakm9X/u0R71N9wwS3RwxHVriKy5n5uYyGy6JN3 D7xR5V8TOuRm0SDBt6T1lWEHUSMQIiqDP4w9iuRex6Zp58QMJMRlxYekyWDD2v02RkIX DLofXRvR/qXJ4qHWM1UctYly2vEX0UfNYXYAakukj2F0W2dkdfDwZfscVWqKQYh+Kjxh pcQR6ZBJaCOMSlCRt6+2zorfNOgWto2UTLNf/D8fk1m3Cygr8JSoCj1hlPZCZ8+LGWId JedX7eEpiR2uH9wiR5MU6VqCyke22Ihk6ltrIHcM5J3ZOBuTSaTmwluYQ4mkcNPDbGNo bcfQ== X-Gm-Message-State: ALoCoQlkWJm/KjUmt+Da3vzIzqiNmz+rcssN+o8KcisvOnZrhhqUbzkeXvYlvECq8/xncMKK0NPR X-Received: by 10.107.132.148 with SMTP id o20mr9608329ioi.31.1440220560200; Fri, 21 Aug 2015 22:16:00 -0700 (PDT) X-BeenThere: std-proposals@isocpp.org Original-Received: by 10.50.176.200 with SMTP id ck8ls683346igc.34.canary; Fri, 21 Aug 2015 22:15:59 -0700 (PDT) X-Received: by 10.50.32.8 with SMTP id e8mr125857igi.8.1440220559510; Fri, 21 Aug 2015 22:15:59 -0700 (PDT) In-Reply-To: <13312961.n5JFXrPRMR@tjmaciei-mobl4> X-Original-Sender: ndospark320@naver.com Precedence: list Mailing-list: list std-proposals@isocpp.org; contact std-proposals+owners@isocpp.org List-ID: X-Spam-Checked-In-Group: std-proposals@isocpp.org X-Google-Group-Id: 399137483710 List-Post: , List-Help: , List-Archive: List-Subscribe: , List-Unsubscribe: , Xref: news.gmane.org gmane.comp.lang.c++.isocpp.proposals:19959 Archived-At: ------=_Part_537_790931100.1440220558026 Content-Type: multipart/alternative; boundary="----=_Part_538_1646266657.1440220558026" ------=_Part_538_1646266657.1440220558026 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: quoted-printable 2015=EB=85=84 8=EC=9B=94 22=EC=9D=BC =ED=86=A0=EC=9A=94=EC=9D=BC =EC=98=A4= =ED=9B=84 1=EC=8B=9C 6=EB=B6=84 29=EC=B4=88 UTC+9, Thiago Macieira =EB=8B= =98=EC=9D=98 =EB=A7=90: > > > What's is P and what is squaring the variable here? How should I interpre= t=20 > the=20 > equal sign above?=20 > P is probability function. It calculates the probability that the=20 expression inside is true. For example: *#include * *discrete_random_variable=20 X(std::uniform_int_distribution(1,6));* This is a variable that represents a die. P(X=3D1) =3D 1/6, P(X=3D2) =3D 1/6, ... , P(X=3D6) =3D 1/6. But what would P(X=3DX) be? Of course a die will always be same number with itself, so P(X=3DX) =3D 1.= =20 But... *discrete_random_variable Y(X);* This is a copy of X. Now I have two dice. Even Y is a perfect copy of X, the dice are different. P(X=3DY) =3D 1/6. Of course, C++ uses =3D=3D as equality, and C++ can't compare three or more= =20 elements at once. So, the expression P(X|Z|) would be written in C++ as somethin= g like=20 this: *compare(And{{X, std::less, bind_variable(std::pow, X, 2)}, {**bind_var= iable(std::pow,=20 X, 2), std::equal, Y}, {Y, std::greater, bind_variable(std::abs, Z)}});* What a mess. > > You cannot.=20 > That was harsh... >_> Maybe I should use pointers instead, as David Krauss= =20 pointed it. Thank you David Krauss. --=20 ---=20 You received this message because you are subscribed to the Google Groups "= ISO C++ Standard - Future Proposals" group. To unsubscribe from this group and stop receiving emails from it, send an e= mail to std-proposals+unsubscribe@isocpp.org. To post to this group, send email to std-proposals@isocpp.org. Visit this group at http://groups.google.com/a/isocpp.org/group/std-proposa= ls/. ------=_Part_538_1646266657.1440220558026 Content-Type: text/html; charset=UTF-8 Content-Transfer-Encoding: quoted-printable


2015=EB=85=84 8=EC=9B=94 22=EC=9D=BC =ED=86=A0=EC= =9A=94=EC=9D=BC =EC=98=A4=ED=9B=84 1=EC=8B=9C 6=EB=B6=84 29=EC=B4=88 UTC+9,= Thiago Macieira =EB=8B=98=EC=9D=98 =EB=A7=90:
=
What's is P and what is squaring the variable here? How should I in= terpret the=20
equal sign above?
P is probability function. It calculates the probabil= ity that the expression inside=C2=A0is true.
For example:
=C2=A0=C2=A0=C2=A0 #include <random>
= =C2=A0=C2=A0=C2=A0 discrete_random_variable<int> X(std::unifo= rm_int_distribution<int>(1,6));
This is a variable= that represents a die.
P(X=3D1)=C2=A0=3D 1/6, P(X=3D2) =3D 1/6, = .... , P(X=3D6) =3D 1/6.
But what would P(X=3DX) be?
Of = course a die will always be same number with itself, so P(X=3DX) =3D 1. But= ....
=C2=A0=C2=A0=C2=A0 discrete_random_variable<int>= ; Y(X);
This is a copy of X. Now I have two dice.
<= div>Even Y is a perfect copy of X, the dice are different.
P(X=3D= Y) =3D 1/6.
Of course, C++ uses =3D=3D as equality, and C++ can&#= 39;t compare three or more elements at once.
So, the expression P= (X<X=C2=B2=3DY>|Z|) would be written=C2=A0in C++=C2=A0as something=C2= =A0like this:
=C2=A0=C2=A0=C2=A0 compare(And{{X, std::les= s, bind_variable(std::pow, X, 2)}, {bind_variable(std::pow= , X, 2), std::equal, Y}, {Y, std::greater, bind_variable(std::abs, Z)}});
What a mess.

You ca= nnot.
That was harsh... >_> Maybe I should use pointe= rs instead, as David=C2=A0Krauss pointed it. Thank you David Krauss.
<= /div>

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