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From: dougm@rice.edu (Doug Moore)
Subject: Re: X to the Y power, how?
Message-ID: <1992Mar2.154651.12261@rice.edu>
Originator: dougm@cs.rice.edu
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Reply-To: dougm@rice.edu (Doug Moore)
Organization: Rice University
References: <50175@hydra.gatech.EDU> <1992Feb27.135250.25403@ux1.cso.uiuc.edu> <1992Feb27.223558.276@rice.edu> <22292@alice.att.com> <omci1INN8np@agate.berkeley.edu> <9206222.13299@mulga.cs.mu.OZ.AU>
Date: Mon, 2 Mar 1992 15:46:51 GMT


In article <9206222.13299@mulga.cs.mu.OZ.AU>, fjh@magnum.cs.mu.OZ.AU (Fergus James HENDERSON) writes:
|> ... I am SICK TO DEATH of the MANY people posting INCORRECT statements to
|> the effect that "well, using '**' would be nice, but it is impossible".
|> 
|> It is QUITE possible to provide a simple interface that allows ** to be used as
|> both for exponentiation and double-indirection.

Okay.  So, if I've overloaded both unary and binary operator * for a
class Foo, and I've overloaded the exponentiation operator ** as well,
what is the meaning of:

Foo a,b,c;
a = b**c;  // b * (*c)?   b (**) c?

Doug Moore
(dougm@cs.rice.edu)