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From: "Jon Andri Sigurdarson" <digit@isholf.is>
Subject: Re: Is this legal C++?
Date: 1998/08/06
Message-ID: <35ca46f5.0@news.isholf.is>#1/1
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If U are using your Bar class in your Foo template class and want to access
the constructor then the:   a.T::Bar()  sentence is not nessesary.  It
really  doesn't do anything what hasn't already been done when U decleare
your variable ( T a; )
So, I don't really get why on earth you wanna make something like:
a.T::T();  work because the constructor is always called when you declare
your variable.
If you wanna call some other functions in the Foo constructor, like I'm
calling Test(),  you have to be sure Test() is always in the class you try
to use with your template class, BUT this is not a good programming habbit
!!!!!!!!!

#include <iostream.h>
class Bar{
public:
 Bar(){cout<<"constructor"<<endl;}
 void Test(){cout<<"test"<<endl;}
 int x;
};
template <class T> class Foo{
public:

(){ 
  T a;
  //a.T::Bar(); // this doesn't do anything
  a.T::Test(); // 
 }
};
int main(int argc, char **argv){
 Foo<Bar> b;
 return 1;
}


I hope this tells you something !

Jon Andri 
mailto:digit@isholf.is



Jason Hunter wrote in message <01bdc100$f82d21b0$19011a12@bwing>...
>I have searched all over the C++ spec to see if this code is correct.  I
>think it ought to be, but I haven't been 
>able to find a compiler (tried, MSVC, Solais c++, Dec c++, Cxx, g++) who
>will compile it.  In fact, they all give
>approximately the same error.  Since this conservation of errors is pretty
>rare among compilers I am beginning
>to think it is in fact not valid.  If it is not valid can someone tell me
>how to do the same thing in a syntacally valid
>way?
>
>here's the code.
>
>
>class Bar
>{
>public:
>  Bar() { }
>
>  int x;
>};
>
>template <class T>
>class Foo
>{
>public:
> Foo() 
> { 
> T a;
>
> a.T::Bar(); // this works!
> a.T::T(); // C2039: 'T' is not a member of Bar.
> }
>};
>
>int main(int argc, char **argv)
>{
> Foo<Bar> b;
>
> return 1;
>}



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