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From: AllanW@my-dejanews.com
Subject: Re: function pointer types(was: Re: atexit() behavior)
Date: 1998/12/02
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In article <74220p$3hl$1@engnews2.Eng.Sun.COM>,
  stephen.clamage@sun.com (Steve Clamage) wrote:
>
> AllanW@my-dejanews.com writes:
>
> >> Does that mean that I can do
> >>
> >> bool is_c_function(void(*)()) { return false; }
> >> extern "C"
> >> {
> >>   bool is_c_function(void(*)()) { return true; }
> >> }
>
> >This is equivalent to what the standard does, and (at least for
> >user-written code) it is illegal.
>
> No, it is legal. The parameters have the linkage of the
> function, and so are different types.
>
> >I think you want is
> >    bool is_c_function(extern "C"   void(*)()) { return true;  }
> >    bool is_c_function(extern "C++" void(*)()) { return false; }
> >The difference here is that we're using two different parameter
> >types, rather than two different return types.
>
> But language linkage can appear only at namespace scope. This
> code is both illegal and unnecessary.

Yes, I see that now; another post of yours pointed me to the correct
section of the standard.

But how would you declare two functions, both with C++ linkage,
both accepting one parameter, where the first function's parameter
is pointer-to-C-function and the second function's parameter is
pointer-to-C++-function?

--
AllanW@my-dejanews.com is a "Spam Magnet" -- never read.
Please reply in USENET only, sorry.

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