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From: "Gabor Greif" <gabor@no.netopia.com>
Subject: [Q] function member template in a template class
Date: 1999/05/04
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{ to moderator: I have posted this days ago, did not seem to have made it.
Nothing on dejanews. Did not got a rejection either... So I repost. }

Here is a question I was not able to answer myself yesterday night...

Suppose having a class template with two parameters and a function member
template in it (returning a two-parameter dependent result):

template <int I, typename T>
struct Res { };


template <int I, typename T>
struct Bar
{
	template <int J>
	typename Res<J, T> foo(void);
};

What is the syntax for defining the function foo outside of the Bar
template?

My attempt was 

template <int I, int J, typename T>
typename Res<J, T> Bar<I, T>::foo<J>(void)
{
	return Res<J, T>();
}


But my compiler rejected it.

Another tricky question:
Assuming I want to define foo for a special case that I == J. Is this
syntax correct?

template <int I, typename T>
typename Res<I, T> Bar<I, T>::foo<I>(void)
{
	return Res<I, T>();
}

But this also busts my compiler.

Can the standards gurus help me in this one?

Thanks in advance...

	Gabor
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