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From: hinnant@_anti-spam_metrowerks.com (Howard Hinnant)
Subject: Re: [Q] function member template in a template class
Date: 1999/05/07
Message-ID: <hinnant-0405991054460001@ith3-285.twcny.rr.com>#1/1
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Approved: Valentin Bonnard <bonnard@clipper.ens.fr>
References: <B3539C4C-1E8FDD@192.168.1.8>
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In article <B3539C4C-1E8FDD@192.168.1.8>, "Gabor Greif"
<gabor@no.netopia.com> wrote:

> { to moderator: I have posted this days ago, did not seem to have made it.
> Nothing on dejanews. Did not got a rejection either... So I repost. }
> 
> Here is a question I was not able to answer myself yesterday night...
> 
> Suppose having a class template with two parameters and a function member
> template in it (returning a two-parameter dependent result):
> 
> template <int I, typename T>
> struct Res { };
> 
> 
> template <int I, typename T>
> struct Bar
> {
>         template <int J>
>         typename Res<J, T> foo(void);
> };
> 
> What is the syntax for defining the function foo outside of the Bar
> template?

This ought to do it:

template <int I, typename T>
struct Res { };


template <int I, typename T>
struct Bar
{
        template <int J>
        typename Res<J, T> foo(void);
};

template <int I, typename T>
template <int J>
typename Res<J, T>
Bar<I, T>::foo(void)
{
   return Res<J, T>();
}

int main()
{
   Bar<1, int> b;
   b.foo<2>();
}

-Howard
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