From 979694941440520596 X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: f78e5,fb1a92fa405c930c X-Google-Attributes: gidf78e5,public From: clamage@eng.sun.com (Steve Clamage) Subject: Re: nested functions Date: 1999/06/10 Message-ID: <7jp0l8$s1r$1@engnews1.eng.sun.com>#1/1 X-Deja-AN: 488088715 Approved: Valentin Bonnard References: <7jd4c5$nup$1@nnrp1.deja.com> <7jjjr6$r02$1@nnrp1.deja.com> <7jma5c$i85@abyss.West.Sun.COM> <37dd56e1.565652003@nntp.ix.netcom.com> X-Original-Date: 10 Jun 1999 18:37:28 GMT Organization: Sun Microsystems Inc., Mountain View, CA X-Auth: PGPMoose V1.1 PGP comp.std.c++ iQBVAwUAN2A3P6wEuYhIxRhxAQEv9wH+M+HO8hOCmhC5ybCmxQzoP4SFEWZaYeRP tZorq/7gJQiPXCEnmFpx5EJc1FtZTjASDpIf1SS0QqDyHkiSHQ/UJg== =WgPD Newsgroups: comp.std.c++ source@netcom.com (David Harmon) writes: >Also, a local function can only be called from within the context of a >function that knows about it. Returning a pointer to a local function >would be undefined, just like returning a pointer to an auto variable. ... >Code elsewhere needs no overhead added to the calling sequence. What about this: typedef int (*fp)(int); extern void foo(fp); int main() { int g(int) { ... } // local function foo(g); // passed to a function that doesn't know about g or main } -- Steve Clamage, stephen.clamage@sun.com --- [ comp.std.c++ is moderated. To submit articles, try just posting with ] [ your news-reader. If that fails, use mailto:std-c++@ncar.ucar.edu ] [ --- Please see the FAQ before posting. --- ] [ FAQ: http://reality.sgi.com/austern_mti/std-c++/faq.html ]