From -420356793639964890 X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: f78e5,fb1a92fa405c930c X-Google-Attributes: gidf78e5,public From: James Kuyper Subject: Re: nested functions Date: 1999/06/23 Message-ID: <3766FDCB.EF02C610@wizard.net>#1/1 X-Deja-AN: 492861361 Content-Transfer-Encoding: 7bit Approved: Valentin Bonnard References: <7jrqf5$op5$1@nnrp1.deja.com> <7jrv0r$dfq$1@engnews1.eng.sun.com> <081650426190c69CPIMSSMTPU07@email.msn.com> <7k0b01$nod$1@panix.com> <7k3fr2$7el@abyss.West.Sun.COM> X-Original-Date: Tue, 15 Jun 1999 21:28:43 -0400 Content-Type: text/plain; charset=us-ascii Organization: Not Enough X-Auth: PGPMoose V1.1 PGP comp.std.c++ iQBVAwUAN3CdsqwEuYhIxRhxAQEG0AH/Qhe77pWPYnNukjTNL9bI9YHz9Mvaurjg +8myNIo5vHaZwWzij9tV4Rhl5rmFZVOLwjMH8ErQRmq7+35PQP9KAA== =zWv8 Mime-Version: 1.0 Newsgroups: comp.std.c++ Stanley Friesen [Contractor] wrote: > > In article <7k0b01$nod$1@panix.com>, > Greg Comeau wrote: > >scope is a syntactic thing. It doesn't apply to a running program > >in the same sense. > > True - but there is this little rule that variables of automatic *duration* > are destroyed on exit from their scope. Not on exit from their scope, but on exit from the block they are defined in. You can have one without the other by executing a subroutine; the block hasn't exited yet, but while the subroutine is executing, the variable isn't in scope. --- [ comp.std.c++ is moderated. To submit articles, try just posting with ] [ your news-reader. If that fails, use mailto:std-c++@ncar.ucar.edu ] [ --- Please see the FAQ before posting. --- ] [ FAQ: http://reality.sgi.com/austern_mti/std-c++/faq.html ]