From 3088401399547263278 X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: f78e5,4e0e65235aa5eceb X-Google-Attributes: gidf78e5,public From: Pete Becker Subject: Re: pointer to member derivation question Date: 1999/06/26 Message-ID: <37737A36.42A64B22@acm.org>#1/1 X-Deja-AN: 494075054 Content-Transfer-Encoding: 7bit Approved: Fergus Henderson References: <7ktjmc$95f$1@nnrp1.deja.com> X-Original-Date: Fri, 25 Jun 1999 08:46:46 -0400 X-Accept-Language: en Content-Type: text/plain; charset=us-ascii X-Complaints-To: news@news.unimelb.edu.au X-Trace: izvestia.its.unimelb.edu.au 930385824 16153 128.250.29.16 (26 Jun 1999 08:30:24 GMT) Organization: Road Runner X-Auth: PGPMoose V1.1 PGP comp.std.c++ iQBFAgUAN3SPkuEDnX0m9pzZAQHQxAF+Pz4xsBti6vq7lyLm8KdHR0+r7Vl2hYSL KKFUestm5cZfDNxPf25xykhEyRiCnmby =wfNV Mime-Version: 1.0 NNTP-Posting-Date: 26 Jun 1999 08:30:24 GMT Newsgroups: comp.std.c++ Jim Hyslop wrote: > > > void f() > > { > > Base Holder::* elt = &Holder::_derived; > > } > Er, I hate to point out the obvious, but doesn't elt require an *object* > to work on, i.e.: No, the code above is correct: elt is a pointer to member data, not an ordinary pointer. There tends to be more discussion about pointers to member functions, so the syntax for a pointer to member data looks disarmingly simple. An ordinary pointer is even simpler: Base * elt = &h._derived; // ordinary pointer --- [ comp.std.c++ is moderated. To submit articles, try just posting with ] [ your news-reader. If that fails, use mailto:std-c++@ncar.ucar.edu ] [ --- Please see the FAQ before posting. --- ] [ FAQ: http://reality.sgi.com/austern_mti/std-c++/faq.html ]