From 5817611104967022888 X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: f78e5,ede379f5dbbc1549 X-Google-Attributes: gidf78e5,public From: niklasb@my-deja.com Subject: Re: Suggestion: "typeof" keyword Date: 1999/08/31 Message-ID: <7qeqk0$a67$1@nnrp1.deja.com>#1/1 X-Deja-AN: 519180466 Approved: Fergus Henderson References: <7nt3vl$1oe$1@nnrp1.deja.com> <7oh7o8$t3f$1@nnrp1.deja.com> <7ol6hi$ej9$2@news.BelWue.DE> <120819991357412479%lisa_lippincott@advisories.com> <37BBDDCA.90D590D4@physik.tu-muenchen.de> <37C3DA57.25C88799@physik.tu-muenchen.de> X-Original-Date: Mon, 30 Aug 1999 20:46:59 GMT X-Http-User-Agent: Mozilla/4.0 (compatible; MSIE 5.0; Windows NT; DigExt) X-Complaints-To: news@news.unimelb.edu.au X-Http-Proxy: 1.0 RED-PRXY-10, 1.0 x36.deja.com:80 (Squid/1.1.22) for client 131.107.3.70 X-Trace: izvestia.its.unimelb.edu.au 936077914 17940 128.250.37.153 (31 Aug 1999 05:38:34 GMT) Organization: Deja.com - Share what you know. Learn what you don't. X-Article-Creation-Date: Mon Aug 30 20:46:59 1999 GMT X-Auth: PGPMoose V1.1 PGP comp.std.c++ iQBFAgUAN8tqReEDnX0m9pzZAQFXzgF9HG/NlMsIY2BqVvQk1VAmnlDxfAyLVpzO r+N5/eE+48++oU+WhGZ9mGh/gTUCgyq8 =3XeT X-MyDeja-Info: XMYDJUIDniklasb NNTP-Posting-Date: 31 Aug 1999 05:38:34 GMT Newsgroups: comp.std.c++ In article <37C3DA57.25C88799@physik.tu-muenchen.de>, Christopher Eltschka wrote: > "Siemel B. Naran" wrote: > > > > On 19 Aug 1999 16:39:34 GMT, Christopher Eltschka > > >"Siemel B. Naran" wrote: > > > > >> In one of my posts I used this > > >> typeof(A*B+C) MultiplyAdd(...) { ... } > > > > >That's problematic: > > > > > >class X {}; > > >class Y { Y operator*(); }; > > >X operator*(X, Y); > > >Y operator*(X*, Y); > > > > > >typeof(X**Y) a > > > > The notation "X*" to mean pointer to an 'X' is wrong. > > According to the current rules of writing types, writing > "X*" to mean "pointer to X" is right. Which simply demonstrates that the operand of typeof should be an expression, not a type. If A, B, and C are types, then typeof(A*B+C) would be illegal because A*B+C is not an expression. What you're looking for, I think, is typeof( A()*B()+C() ) or if you prefer cast notation: typeof( (A)0 * (B)0 + (C)0 ) Either could be read, "the type of (the result of) an expression that: adds two objects of types A and B, and then adds their sum with an object of type C." Sent via Deja.com http://www.deja.com/ Share what you know. Learn what you don't. --- [ comp.std.c++ is moderated. To submit articles, try just posting with ] [ your news-reader. If that fails, use mailto:std-c++@ncar.ucar.edu ] [ --- Please see the FAQ before posting. --- ] [ FAQ: http://reality.sgi.com/austern_mti/std-c++/faq.html ]