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From: "Michael Kochetkov" <mkochetk@trustworks.commm>
Subject: Re: templated Copy-Constructor?
Date: 2000/04/29
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Newsgroups: comp.std.c++

14.5.2/2 -- "A  normal  (non-template)  member  function   with  a given
name and type and a member function template of the same   name, which could
be used to generate a  specialization  of  the  same   type,  can  both be
declared in a class.  When both exist, a use of that name and type  refers
to the non-template member unless an explicit template  argument  list  is
supplied."

With regards,
Michael Kochetkov.

"Stephan Keil" <kei@parsytec.de> wrote in message
news:39099e33$0$22977@businessnews.de.uu.net...
> Hi,
>
> consider the following example:
>
>  template<class T>
>  struct Blah
>  {
>   Blah(){}
>
>   template<class U>
>   Blah(const Blah<U>&)
>   {
>    cout << "Blah" << endl;
>   }
>  };
>
>  Blah<double> bd(Blah<int>());
>  Blah<int> bi(Blah<int>());
>
> With VC++ 6.0 the construction of 'bd' invokes the templated
> constructor where as the construction of 'bi' does not
> (i.e. apparently the compiler generated copy constructor
> is used instead). Is this correct behaviour according to
> the standard?
>
> thanks for comments,
>
> Stephan
>
>
>
> ---
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