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From: Ron Natalie <ron@sensor.com>
Subject: Re: templated Copy-Constructor?
Date: 2000/04/29
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Stephan Keil wrote:
> 

>   template<class U>
>   Blah(const Blah<U>&)
>   {
>    cout << "Blah" << endl;
>   }
>  };
> 
>  Blah<double> bd(Blah<int>());
>  Blah<int> bi(Blah<int>());
> 

You're not just defining a copy constructor above,
you're defining an constructor that takes an arbitrary type.
Is this what you want?  If you want to define a copy
constructor then :

	Blah(const Blah&) {
	  ...
	}

would have been sufficient.

But getting back to your question.  No, this template member should not
be called.  A non-templated member (even an implicitly generated one)
will be preferred over a templated one.

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