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From: llewellyat@dbritschdot.dsldot.xmissiondot.com
Subject: Re: integer types
Date: 2000/07/02
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James Kuyper <kuyper@wizard.net> writes:

> Greg Brewer wrote:
> > 
> > That was my guess.  I was unsure about MS support.  It's one of those things
> > that I use if I must but avoid if I can.  I've been stuck on a problem
> > because I lack a 64bit integer; this allows me to proceed until a long long
> > becomes available.  I wish there was a way to detect its availability; sort
> > of a
> >   #if defined(long long)
> >       long long f(void);
> >   #else
> >       __int64 f(void);
> >   #endif
> > coding.
> 
> In C99, you can write the following:
> 
> #include <stdint.h>
> #ifdef INT64_MAX
> 	// The optional type with exactly 64 bits exists
> 	int64_t	f(void);
> #else
> 	// The type with at least 64 bits is mandatory
> 	int_least64_t f(void);
> #endif
> 
> I think you can reasonably assume that future versions of the C++
> standard will borrow this feature of C99. C++ compilers that share code
> with C99 compilers will probably provide <stdint.h> as an extension much
> earlier than that.

hm... since most (all?) of <stdint.h> can be implemented as typedefs,
  (well, actually that assumes already having a 64 bit integral type;
  I guess I am too used to the ubiquity of 'long long' on unices)
  I would suspect it will be a matter of whether <stdint.h> comes with
  the compiler / c library.

(As one example, gcc (freestanding C compiler) does not support
  int64_t and friends. However, if the system C library has
  <stdint.h>, (linux with glibc >= 2.1.2 being one example), int64_t
  etc work fine with C++, as they are only typedefs. )

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